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ojciec pijo edited comment on THRIFT-1226 at 6/29/11 10:13 PM: --------------------------------------------------------------- I think there's no java serialization spec per se, but default mechanism always keeps references if particular instance is saved to the same stream more than once. it is mentioned here: http://java.sun.com/developer/technicalArticles/Programming/serialization/ ("Caching Objects in the Stream"). For a testcase, I have generated the same pair of objects with Thrift 5 and 6. Test passes for Thrift5, fails for Thrift6: [...] @Test public void testVersion5() throws Exception { A5 a = new A5(); B5 b = new B5(); //add the same instance twice b.addToItems(a); b.addToItems(a); B5 deserialized = (B5)serializeAndDeserialize(b); //with java serialization //we expect that references are preserved and [0] == [1] assertSame(deserialized.getItems().get(0), deserialized.getItems().get(1)); } @Test public void testVersion6() throws Exception { A6 a = new A6(); B6 b = new B6(); //add the same instance twice b.addToItems(a); b.addToItems(a); B6 deserialized = (B6)serializeAndDeserialize(b); //since Thrift6 overrides default java serialization by providing readObject/writeObject, //now it behaves in 'thrift' way - references are replaced by copies //and this assertion FAILS! assertSame(deserialized.getItems().get(0), deserialized.getItems().get(1)); } was (Author: ojciecpijo): I think there's no java serialization spec per se, but default mechanism always keeps references if particular instance is saved to the same stream more than once. it is mentioned here: http://java.sun.com/developer/technicalArticles/Programming/serialization/ ("Caching Objects in the Stream"). For a testcase, I have generated the same pair of objects with Thrift 5 and 6. Test passes for Thrift5, fails for Thrift6: [...] @Test public void testVersion5() throws Exception { A5 a = new A5(); B5 b = new B5(); //add the same instance twice b.addToItems(a); b.addToItems(a); B5 deserialized = (B5)serializeAndDeserialize(b); //with java serialization //we expect that references are preserved and [0] == [1] assertSame(deserialized.getItems().get(0), deserialized.getItems().get(1)); } @Test public void testVersion6() throws Exception { A6 a = new A6(); B6 b = new B6(); //add the same instance twice b.addToItems(a); b.addToItems(a); B6 deserialized = (B6)serializeAndDeserialize(b); //since Thrift6 overrides default java serialization by providing readObject/writeObject, //now it behaves in 'thrift' way - references are replaced by copies //and this assertion FAILS! assertSame(deserialized.getItems().get(0), deserialized.getItems().get(1)); } > command line option to disable overriding java serialization > ------------------------------------------------------------ > > Key: THRIFT-1226 > URL: https://issues.apache.org/jira/browse/THRIFT-1226 > Project: Thrift > Issue Type: Improvement > Components: Java - Compiler > Affects Versions: 0.6, 0.6.1 > Reporter: ojciec pijo > Attachments: testcase.zip > > > bugfix THRIFT-1038 is a breaking change since it overrides default java > serialization mechanism. as a result, objects generated by Thrift v6 are not > compatible with java serialization rules (references between objects are lost > after deserialization). Please provide a command line parameter to disable > generating readObject/writeObject as a workaround. -- This message is automatically generated by JIRA. For more information on JIRA, see: http://www.atlassian.com/software/jira