RE: hasId

[pieter gmail]

Hi,

The following code illustrates my concern/confusion.
    @Test
    public void testHasId() {
        final TinkerGraph graph = TinkerGraph.open();
        Vertex a = graph.addVertex(T.label, "A");
        Vertex b = graph.addVertex(T.label, "B");

        List<Vertex> vertices = 
graph.traversal().V().hasId(a.id()).hasId(b.id()).toList();
        Assert.assertTrue(vertices.isEmpty());
    }

The test fails as the both vertices are returned.
Is this expected, I expected 'and' not 'or' behavior.

Similar to,

    @Test
    public void testHasLabel() {
        final TinkerGraph graph = TinkerGraph.open();
        Vertex a = graph.addVertex(T.label, "A");
        Vertex b = graph.addVertex(T.label, "B");

        List<Vertex> vertices = 
graph.traversal().V().hasLabel("A").hasLabel("B").toList();
        Assert.assertTrue(vertices.isEmpty());
    }

This one passes.

I checked the docs,

|hasLabel(labels...)|: Remove the traverser if its element does not have 
any of the labels.
|hasId(ids...)|: Remove the traverser if its element does not have any 
of the ids.

Seems they should behave the same?

I am working on version 3.2.4

Thanks
Pieter