Github user jorgebay commented on a diff in the pull request:

    https://github.com/apache/tinkerpop/pull/747#discussion_r152230125
  
    --- Diff: gremlin-test/features/sideEffect/Sack.feature ---
    @@ -0,0 +1,71 @@
    +# Licensed to the Apache Software Foundation (ASF) under one
    +# or more contributor license agreements.  See the NOTICE file
    +# distributed with this work for additional information
    +# regarding copyright ownership.  The ASF licenses this file
    +# to you under the Apache License, Version 2.0 (the
    +# "License"); you may not use this file except in compliance
    +# with the License.  You may obtain a copy of the License at
    +#
    +# http://www.apache.org/licenses/LICENSE-2.0
    +#
    +# Unless required by applicable law or agreed to in writing,
    +# software distributed under the License is distributed on an
    +# "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
    +# KIND, either express or implied.  See the License for the
    +# specific language governing permissions and limitations
    +# under the License.
    +
    +Feature: Step - sack()
    +
    +  Scenario: g_withSackXhelloX_V_outE_sackXassignX_byXlabelX_inV_sack
    +    Given the modern graph
    +    And the traversal of
    +      """
    +      
g.withSack("hello").V().outE().sack(Operator.assign).by(T.label).inV().sack()
    +      """
    +    When iterated to list
    +    Then the result should be unordered
    +      | result |
    +      | created |
    +      | knows |
    +      | knows |
    +      | created |
    +      | created |
    +      | created |
    +
    +  Scenario: g_withSackX0X_V_outE_sackXsumX_byXweightX_inV_sack_sum
    +    Given the modern graph
    +    And the traversal of
    +      """
    +      
g.withSack(0.0).V().outE().sack(Operator.sum).by("weight").inV().sack().sum()
    +      """
    +    When iterated to list
    +    Then the result should be unordered
    +      | result |
    +      | d[3.5].m |
    +
    +  Scenario: 
g_withSackX0X_V_repeatXoutE_sackXsumX_byXweightX_inVX_timesX2X_sack
    +    Given the modern graph
    +    And the traversal of
    +      """
    +      
g.withSack(0.0).V().repeat(__.outE().sack(Operator.sum).by("weight").inV()).times(2).sack()
    +      """
    +    When iterated to list
    +    Then the result should be unordered
    +      | result |
    +      | d[2.0].d |
    --- End diff --
    
    These two are also big decimal...


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