>  In this case, both threads will
> continue running the function with ?replaced? bit turned on and the oldValue
> of both thread will point to the same location. This means that the value of
> the first thread that did the put operation will not be treated as a value
> that was replaced.
> 
> Could you please let me know whether you consider this as a bug?

Is it any different than if two threads invoke the operation serially?

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