hello,when I run usergrid-rest access link:http://localhost:8080/usergrid-rest/status response: { "error": "uncaught", "timestamp": 1445572529016, "duration": 119, "exception": "org.apache.usergrid.rest.exceptions.UncaughtException", "error_description": "Internal Server Error", "error_id": "e664f258-7939-11e5-954f-a41731054ba5" } console error: 2015-10-23 11:48:08,110 ERROR (Notifications_Processor026b090c-7518-417a-b0c9-0bfd6b036866) [org.apache.usergrid.services.ServiceManager] - Failed to get application java.lang.RuntimeException: application id {b6768a08-b5d5-11e3-a495-11ddb1de66c8} is returning null at org.apache.usergrid.services.ServiceManager.init(ServiceManager.java:103) at org.apache.usergrid.services.ServiceManagerFactory.getServiceManager(ServiceManagerFactory.java:69) at org.apache.usergrid.services.notifications.QueueListener.execute(QueueListener.java:147) at org.apache.usergrid.services.notifications.QueueListener.access$0(QueueListener.java:137) at org.apache.usergrid.services.notifications.QueueListener$1.run(QueueListener.java:123) at java.util.concurrent.Executors$RunnableAdapter.call(Unknown Source) at java.util.concurrent.FutureTask.run(Unknown Source) at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source) at java.util.concurrent.ThreadPoolExecuto Environment: usergrid : 2.1 release cassandra : apache-cassandra-2.1.8 web server: tomcat 7 uuid define: i find this define on org.apache.usergrid.corepersistence.util.CpNamingUtils, public static final UUID MANAGEMENT_APPLICATION_ID = UUID.fromString( "b6768a08-b5d5-11e3-a495-11ddb1de66c8" ); other: if has demo cql for cassandra,can you tell me ? I create cassandra keyspaces like usergrid docs,but error is alwith appear. this error probably I missing column family data,but I try more times ,but No solution,so I Seek help,hope get you help,thanks.
