On Mon, Apr 21, 2014 at 8:21 PM, Chamil Jeewantha <cha...@wso2.com> wrote:
> B.staticMethod() is already thread safe (it is synchronized). because of > that, the caller class (Class A) do not need to use a lock again. > > Yes. And this stackoverflaw answer[1] gives a tip [1] http://stackoverflow.com/questions/5443297/concurrency-in-java-synchronized-static-methods On Mon, Apr 21, 2014 at 8:04 PM, Sohani Weerasinghe <soh...@wso2.com> wrote: > Hi All, > > Since synchronization on static methods is a class level locking a second > thread can't access the method until first thread releases the lock. The > static method has synchronized as shown below. > > public class B{ > public *synchronized* static void staticMethod(String a){ > } > } > > If this method calls by another class (Class A), then do I have to use a > synchronized block as shown below to avoid multiple threads accessing the > static method? > > Public class A { > *private static Object lock = new Object();* > > public static void main(String[] args){ > *synchronized(lock){* > B.staticMethod("hello"); > *}* > } > } > > Can someone provide a solution on this ? > > Regards, > Sohani > > Sohani Weerasinghe > Software Engineer > WSO2, Inc: http://wso2.com > > Mobile : +94 716439774 > Blog :http://christinetechtips.blogspot.com/ > Twitter : https://twitter.com/sohanichristine > > _______________________________________________ > Dev mailing list > Dev@wso2.org > http://wso2.org/cgi-bin/mailman/listinfo/dev > > -- K.D. Chamil Jeewantha Associate Technical Lead WSO2, Inc.; http://wso2.com Mobile: +94716813892 > _______________________________________________ > Dev mailing list > Dev@wso2.org > http://wso2.org/cgi-bin/mailman/listinfo/dev > > -- *Malintha Adikari* Software Engineer WSO2 Inc.; http://wso2.com lean.enterprise.middleware Mobile: +94 71 2312958 Blog: http://malinthas.blogspot.com Page: http://about.me/malintha (): උපදිෂ්ට, ද්වෙෂ කරනවා, ද්වේෂ කරනවා, පිළිකුල් කරනවා, x ලකුණ, ලකුණ යොදනවා, වකුටු, ස්වරිතස්වරය ඇඟවීමට යොදන ලකුණ, යමක් කල යුතුයි
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