Hi, I have developed a Jaggery app to our training project and i needed to do a Jaggery post and handle some error cases if the response fails. I went through the documentation but i could not find a Post error method. So as for a work around i checked the returned code using userInfo.xhr.status and did the logic. I'm not sure whether its a good approach to do so. Can some please tel me if there's a method to handle that.
For success the method is, success(data:Object, xhr:Object) as per the documentation. Regards, Damith -- Software Engineer WSO2 Inc.; http://wso2.com <http://www.google.com/url?q=http%3A%2F%2Fwso2.com&sa=D&sntz=1&usg=AFQjCNEZvyc0uMD1HhBaEGCBxs6e9fBObg> lean.enterprise.middleware mobile: *+94728671315*
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