Apparently overloading is not working, but the error message I get is questionable.
I Just created the following classes:
animal()
{
void talk()
{
print "animal talk";
}
}
dog() extends animal
{
void talk(int z)
{
print "dog talk";
}
}
Now I get the error message "an overloaded function has an incorrect number of parameters".
It is because I added the parameter the method became overloaded.
So I think overloading is not possible. Maybe someone out there has an example that shows the opposite.
regards,
Danny
Jens Fudge <[EMAIL PROTECTED]> wrote:
Normally in OOP there are these "definitions"
override a method:
In an inherited class, you can override a method with the same number of
parameters, where the parameters must be of the same type as the ancestor.
Hence when you call the method, you don't see any difference in the method
calls. In Axapta you may call Super() as to also have the ancestors code
run.
I think Axapta even calls it overwrite
overload a method:
This is done in either one level or more levels of inheritance. It simply
means that you can have two or more methods with the same name. The methods
must then differ in the parameterlist. Either by number or by type.
I do not think that its possible to overload in Axapta.
Jens Fudge
"dgaethofs"
<[EMAIL PROTECTED]
com> To
[EMAIL PROTECTED]
26-07-2004 15:23 cc
Subject
Please respond to [development-axapta] Override
development-axapt versus Overload
[EMAIL PROTECTED]
Dear all,
I have a question about the difference between override and
overload. In the developers guide one talks about the two as if they
are the same. But they are not.
Can we overload methods in Axapta ?
What exactly is meant with overloading in Axapta?
Regards,
Danny
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