Use the below stmt after 'super()' in Init method of the form.
element.control(Control::xx).visible(false); // xx is the form control name
(Group/Field).
Hope this helps!
Regards,
Diwakar
________________________________
From: shamika <shamik...@yahoo.com>
To: development-axapta@yahoogroups.com
Sent: Thursday, 17 September, 2009 10:06:02 PM
Subject: [development-axapta] FormControl Declaration Problem
Hello,
I want to show one formcontrol based upon dataareaid.
But that control is attached to respective table field group and that field
group is used as is in Form Design - > Group. So basically I cannot setup
"AutoDeclaration" property to Yes as it is disabled.
So When I tried to declare the same in CLassDeclaration method as
FormControl _nameofcontrol;
and then in init() -> I wrote _nameofcontrol. visible(false) based upon
dataareaid.
It gives me error that " FormControl is not initialized" .
How am I suppose to initilize it? Or Is there any other method to handle this
situation?
Please advise me.
Thanks,
Sam
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