On 05/24/2012 09:22 PM, Dong Aisheng wrote:
> On Thu, May 24, 2012 at 11:22:13PM +0800, Stephen Warren wrote:
...
>> The problem is this:
>>
>> Thread 1: Call of_node_to_gpiochip(), returns a gpio_chip.
>> Thread 2: Unregisters the same gpio_chip that was returned above.
>> Thread 1: Accesses the now unregistered (and possibly free'd) gpio_chip
>> -> at best, bad data, at worst, OOPS.
>>
> Correct. We did have this issue.
> Thanks for clarify.
>
>> In order to prevent this, of_node_to_gpiochip() should take measures to
>> prevent another thread from unregistering the gpio_chip until thread 1
>> has completed its step above.
>>
>> The existing of_get_named_gpio_flags() is safe from this, since
>> gpiochip_find() acquires the GPIO lock, and all accesses to the fouond
>> gpio chip occur with that lock held, inside the match function. Perhaps
>> a similar approach could be used here.
>
> Why it looks to me of_get_named_gpio_flags has the same issue and also not
> safe?
> For of_node_to_gpiochip itself called in of_get_named_gpio_flags, it's safe.
Uggh. Yes, I meant that of_node_to_gpiochip() itself doesn't have this
issue, but you're right, it looks like of_get_named_gpio_flags() does.
> But after that, i'm suspecting it has the same issue as you described above,
> right?
>
> For example:
> int of_get_named_gpio_flags(struct device_node *np, const char *propname,
> int index, enum of_gpio_flags *flags)
> {
> ...
> gc = of_node_to_gpiochip(gpiospec.np);
> if (!gc) {
> pr_debug("%s: gpio controller %s isn't registered\n",
> np->full_name, gpiospec.np->full_name);
> ret = -ENODEV;
> goto err1;
> }
>
> ===> the gc may be unregistered here by another thread and
> even already have been freed, right?
>
> ret = gc->of_xlate(gc, &gpiospec, flags);
> ...
> }
>
> Maybe we need get the lock in of_node_to_gpiochip and release it by calling
> of_gpio_put(..) after using?
Yes, something like that; it should take the module lock, not the gpio lock.
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