On Tue, Jul 29, 2014 at 10:46:13AM +0100, Mark Rutland wrote:
> > +   - big-endian : If this property is absent, the native endian mode will
> > +                 be in use as default, or the big endian mode will be in 
> > use
> > +                 for all the device registers.
> 
> Native endian is meaningless. If a CPU supports both BE and LE, there is
> no native endianness. The endianness of the kernel is dynamic while the
> endianness of registers in HW is fixed. 
> 
> Just choose an endianness to assume by default (presumably little). That
> way this describes the HW and always works with a kernel of arbitrary
> endianness.

Thank you for the comments.

I just revised it by using 'little endian as default' and sent the patch v6.

Please take a look at the new version.

Thanks again,
Nicolin

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