On Saturday, 31 May 2014 at 17:49:18 UTC, Jesse Phillips wrote:
On Saturday, 31 May 2014 at 07:32:22 UTC, Kagamin wrote:
What do you mean "D does not provide a decltype"?
typeof(cx) my_cx2 = cx;
I'll blame this on my poor knowledge of C++, at this time
typeof in C++ does not appear to compile, in the way I'm trying
to use it. I thought using typeof in C++ would result in the
same answer as the deduction auto provides.
From that point of view, there is no need for decltype, because
typeof already gives you the actual type in D (which will be
the same as the type at declaration).
I think you've misunderstood him. You say in the article "D does
not provide decltype", he is saying that this is misleading: D
does but it's just called typeof instead.
