http://d.puremagic.com/issues/show_bug.cgi?id=3000
Summary: iota should work with floats
Product: D
Version: 2.030
Platform: PC
OS/Version: Windows
Status: NEW
Severity: normal
Priority: P2
Component: Phobos
AssignedTo: bugzi...@digitalmars.com
ReportedBy: dsim...@yahoo.com
import std.range;
void main() {
auto foo = iota(0.0L, 10.0L, 1.0L);
}
The above doesn't compile and results in a bunch of long errors that aren't
particularly useful for diagnosing the cause of the problem. The real problem
is
line 2089, range.d:
return take((end - begin + step - 1) / step, Seq(tuple(begin, step), 0u));
The problem is that, if the arguments to iota are floats, not ints, the number
of elements take() is told to take is a float, not an int. This can be fixed
trivially by changing that line to:
return take(cast(size_t) ((end - begin + step - 1) / step), Seq(tuple(begin,
step), 0u));
Also, take() should probably use a ulong, not a size_t. I could picture
someone wanting to run a long monte carlo simulation, for example, by taking
more than 4 billion elements from an infinite range of random numbers.
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