http://d.puremagic.com/issues/show_bug.cgi?id=10437
--- Comment #3 from q...@web.de 2013-06-21 06:30:37 PDT --- (In reply to comment #1) > What will occur with template function? > > import std.conv : to; > > T convert(T, S)(S src) > { > return to!T(src); > } > > void main() {} > // template function convert is not instantiated. > > In this case, imported std.conv is unused then compiler might warn it. Is this > right? I think the question is misleading. The actual question is how clever the analysis is. Call-graph information provides a similar scenario: import std.stdio; void foo() { writeln("foo"); } void main () {} // foo is never called In such scenarios, deleting a statement might declare a whole chain (actually DAG) of (template or normal) functions unused. It is a question of taste, if the user should be flooded with warnings in this case. -- Configure issuemail: http://d.puremagic.com/issues/userprefs.cgi?tab=email ------- You are receiving this mail because: -------