https://issues.dlang.org/show_bug.cgi?id=17476
--- Comment #7 from Mathias Lang <mathias.l...@sociomantic.com> --- When a thread runs I would expect the following (simplified) course of action: - Initialize the TLS data - Do the writeln - Exit Given the original code, I would then expect the code to print 3 times "/some/string/initializer" and one time "foobar". I would not expect any order. Which means the first 2 runs give a perfectly valid output. However, the 3rd run outputs "/some/string/initializer" twice, and "foobar" twice. How can "foobar" be printed twice if it's only set for one thread ? If the delegate generated from the `foreach` body would capture the static instance of the main thread, we would get 4 "foobar". but we don't. --
