Nick Sabalausky wrote:
Is there an idiom, preferably D1, to detect whether or not the code is
currently executing as a ctfe?
Ie:
void foo()
{
(static?) if( ???? )
{
// Run-time code here
// that does stuff the CTFE engine chokes on
}
else
{
// CTFE code here
// that might not be ideal, but at least works as CTFE
}
}
Not currently, but you can use the following hack, which exploits a bug
with CTFE (if the bug gets fixed then the code below won't work):
----
import tango.io.Stdout;
bool isCtfe()
{
void test( char[] str )
{
str[0] = 'b';
}
char[] a = "foo".dup;
test(a);
if( a == "boo" )
return false;
return true;
}
const ctfe = isCtfe();
void main()
{
Stdout.formatln( "CTFE: {}; Runtime: {};", ctfe, isCtfe() );
}
----
