-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Steven Schveighoffer wrote: > If I have 2 identical floating point values, how do I ensure they are > binary equivalents of eachother? I'm trying to write some > unittest/assert code, and it's not exactly trivial. > > I thought 'a is b' would work, but it just morphs into a == b, which > isn't helpful. Why doesn't 'is' just do a bit compare for floating points? > > -Steve
Just out of curiosity; how many cases are there where a == b and they have different bit patterns? I can only think of +-0. Otherwise you can only get that with denormalised floats; which you won't get on an x86 processor. - -- My enormous talent is exceeded only by my outrageous laziness. http://www.ssTk.co.uk -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.7 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iD8DBQFLK86uT9LetA9XoXwRAvtsAKDDoX6EzXj+wOIgTVHDzkRF0vXGsgCdH6tX QLvFQxYyjIwk7Qxi13VyrCI= =M18X -----END PGP SIGNATURE-----
