On 22/06/2010 07:29, Jonathan M Davis wrote:
Okay. If you call until like sostr.until('\"') you get a Until!(pred,string,char). I want to turn that into a string. array() doesn't seem to do the trick right now. It used to work, but now it gives me main.d(47): Error: template std.array.array(Range) if (isForwardRange! (Range)) does not match any function template declaration main.d(47): Error: template std.array.array(Range) if (isForwardRange! (Range)) cannot deduce template function from argument types !()(Until! (pred,string,char)) to!string just converts it into a string with the Until! stuff being included in the string rather than giving me the actual result, so that doesn't work. So, what is the correct and preferred way to convert the result of Until! to as string when you were searching on a string in the first place? The std.algorithm functions are definitely nice, but they have tendancy to return hard-to-use types. - Jonathan M Davis
Could be wrong, but strings aren't (conceptually) arrays any more. They are bidirectional ranges which is why the array call doesn't work. Though how you actually get a string back I don't know. -- My enormous talent is exceeded only by my outrageous laziness. http://www.ssTk.co.uk
