simendsjo <simen.end...@pandavre.com> wrote:
The spec for array says:
Static arrays are value types. Unlike in C and D version 1, static
arrays are passed to functions by value. Static arrays can also be
returned by functions.
I don't get the "static arrays are passed to functions by value" part.
Here I am passing in a static and dynamic array. Both are passed by
value, and the function can modify the array of both
{
void func(int[] arr, void* ptr) {
The problem is here ^^
What your function signature is saying, is 'pass arr to me as if a
dynamic array'. If you want to pass a static array, define the function
like this, and you will see magic at work:
void func( int[3] arr, void* ptr ) {
arr[0] = 9;
assert(&arr != ptr);
}
int[3] a = [1,2,3];
func(a, &a);
This call is equivalent to func( a[], &a );. Since your function says
to treat the array as dynamic, a slice is created from your static array.
assert(a == [9,2,3]); // changed..
int[] b = [1,2,3];
func(b, &b);
assert(b == [9,2,3]);
}
--
Simen
