On 2010-09-07 17:34, Stanislav Blinov wrote:
07.09.2010 17:00, Jacob Carlborg пишет:
I'm reading http://www.digitalmars.com/d/2.0/declaration.html#Typeof
where it says:
"typeof(this) will generate the type of what this would be in a
non-static member function, even if not in a member function. "
From that I got the impression that the code below would print the
same result, but it doesn't. It prints:
main.Bar
main.Foo
instead of:
main.Foo
main.Foo
Is this a bug or have I misunderstood the docs?
module main;
import std.stdio;
class Bar
{
void method ()
{
writeln(typeid(typeof(this)));
writeln(typeid(this));
}
}
class Foo : Bar {}
void main ()
{
auto foo = new Foo;
foo.method;
}
I don't think it's a bug. More of it, Expressions page in the docs has
your very same example in Typeid section.
Inside Bar.method, typeof(this) yields a type (Bar), and typeid for
types gets you, well, typeid for types :) typeid(this), hovewer, should
get typeinfo for most derived class, which it does.
No it's not the same example. In the example on the Expressions page
typeid is used on the static type A with the dynamic type B. I have both
the static and dynamic type Foo. I think in my example the compiler have
all the necessary information at compile time and typeof(this) would
resolve to the type of the receiver, i.e. the type of "foo" which is Foo.
--
/Jacob Carlborg
