On 09/10/2010 04:40 AM, Andrej Mitrovic wrote:
I'm trying to use algorithm.copy, but I get back nothing in the copy buffer.
How do I to copy an array of ubyte's?
iimport std.algorithm,
std.concurrency,
std.stdio;
void main()
{
enum bufferSize = 4;
auto tid = spawn(&fileWriter);
// Read loop
foreach (ubyte[] buffer; stdin.byChunk(bufferSize))
{
immutable(ubyte)[] copy_buffer;
copy(buffer, copy_buffer);
writeln(copy_buffer); // writes nothing
send(tid, copy_buffer);
}
}
void fileWriter()
{
while (true)
{
auto buffer = receiveOnly!(immutable(ubyte)[])();
// writeln(buffer);
}
}
Andrej Mitrovic Wrote:
This is from TDPL page 407:
import std.algorithm,
std.concurrency,
std.stdio;
void main()
{
enum bufferSize = 1024 * 100;
auto tid = spawn(&fileWriter);
// Read loop
foreach (immutable(ubyte)[] buffer; stdin.byChunk(bufferSize))
{
send(tid, buffer);
}
}
void fileWriter()
{
// write loop
while (true)
{
auto buffer = receiveOnly!(immutable(ubyte)[])();
tgt.write(buffer);
}
}
Error:
C:\DMD\dmd2\windows\bin\..\..\src\phobos\std\stdio.d(1943):
Error: cannot implicitly convert expression (buffer) of type ubyte[]
to immutable(ubyte)[]
Yet interestingly I can't use type inference:
foreach (buffer; stdin.byChunk(bufferSize))
{
send(tid, buffer);
}
Error: stdin_stdout_copy.d(11): Error: cannot infer type for buffer
But in the original code I get back a mutable ubyte[] which I can't implicitly
convert to immutable (I'd need a copy first). There's no .dup or .idup property
for stdin.byChunk. So what am I supossed to do here?
std.algorithm.copy will copy an input range into an output range. An
array is a valid output range, but does not append as you seem to
expect. Instead, it fills the array.
int[] a = new int[](3);
copy([1,2,3],a);
assert (a == [1,2,3]);
To get an output range which appends to an array, use appender.
In this case, however, you simply want buffer.idup; :-)