a while ago, I assumed that
e1 += e2
gets rewritten as
e1 = e1 + e2
Yeah. It doesn't. It doesn't even behave the same wrt erroneously typed
arguments
On 11/15/2010 02:35 PM, Jonathan M Davis wrote:
As far as is, it doesn't explicitly say that rewriting is done, but, it
does spell out that to do the opposite, use !is. Maybe the spec should be
updated to explicitly say x !is y is the same as !(x is y).
Honestly, I don't see how it could be otherwise. I would have just assumed that
they were identical.
- Jonathan M Davis
