On Fri, 03 Dec 2010 16:53:04 -0500, Michal Minich
<michal.min...@gmail.com> wrote:
On Fri, 03 Dec 2010 16:44:42 -0500, Steven Schveighoffer wrote:
On Fri, 03 Dec 2010 16:34:51 -0500, Michal Minich
<michal.min...@gmail.com> wrote:
What is performance overhead for casting value of type int to uint and
in the opposite direction. What happen when I cast int to int or uint
to uint
Nothing, there is no performance, type is strictly a compile-time
concept.
(for the simplicity in generic code). I suppose there is no difference,
and it is in fact no-op for processor - it depends only on
interpretation. Only when making other operations compiler may generate
different instruction when he considers some value of either of types.
Am I right?
Not sure what you mean by that last part...
-Steve
just that i + i generates different instructions than ui + ui where int
i; uint ui;
Not really important, because I'm currently interested in cast only.
Thank you.
That is odd, I would think that i+i generates the same instructions as
ui+ui. As far as I know, adding unsigned and signed is the same
instruction, but unsigned add just ignores the carry bit.
-Steve
