Re: Exactly Replicating a Function's Signature?

[Jacob Carlborg]

On 2011-01-19 16:29, Andrej Mitrovic wrote:

Is this what you're looking for?:

import std.stdio;
import std.traits;

void test(alias F)()
{
     ReturnType!(F) otherFunc(ParameterTypeTuple!(F))
     {
         typeof(return) result;
         return result;
     }
}

double foo(int x, int y)
{
     double result;
     return x + y * 2.5;
}

void main()
{
     test!foo;
}

Will that keep: ref, out, inout and so on in the signature ?

--
/Jacob Carlborg