On Wed, 02 Feb 2011 11:35:50 -0500, spir <denis.s...@gmail.com> wrote:
On 02/02/2011 04:20 PM, Lars T. Kyllingstad wrote:
I think the compiler does a bitwise comparison in this case, meaning
that
it compares the arrays' pointers instead of their data. Related bug
report:
Thank you, Lars.
In fact, I do not really understand what you mean. But it helped me
think further :-)
I couldn't get from all your posts that you understand the issue. A
bitwise comparison compares ONLY the bits in the struct, NOT what the
struct points to.
Comparing two arrays compares the data they point to. So what is
happening is essentially, the struct default comparison is comparing that
both strings are equal in the identity sense, i.e. they both point to the
exact same data with the exact same length.
If you analyze a string array, it looks like this (switch to mono-spaced
font now :) :
+----------------------+
|int length |
|immutable(char) *ptr -|------> "hello world"
+----------------------+
The pointer points to the data, it is not contained within the array
"head". The bitwise comparison only compares the head (what's in the box).
Apologies if you already understood this, but I wanted to be sure that you
"got it."
-Steve
