On Thu, Sep 17, 2020 at 02:58:48PM +0000, drathier via Digitalmars-d-learn
wrote:
> What's the proper way to exit with a specific exit code?
>
> I found a bunch of old threads discussing this, making sure
> destructors run and the runtime terminates properly, all of which
> seemingly concluding that it's sad that there isn't a way to do this
> easily, but hopefully things have changed in the last 5-10 years and
> I'm just missing the obvious solution.
AFAIK, there still isn't an "official" way to do this besides return
the exit code from main(). My go-to solution is to declare an
ExitException that's explicitly caught by main():
class ExitException : Exception {
int returnCode;
this() { super("exit"); }
}
void exit(int rc=0) { throw new ExitException(rc); }
int main(string[] args) {
try {
... // your code here
exit(123);
...
} catch (ExitException e) {
return e.returnCode;
}
return 0;
}
Caveat: this may or may not do the Right Thing(tm) in a multithreaded
application.
T
--
Talk is cheap. Whining is actually free. -- Lars Wirzenius
