Re: Cannot deduce function from argument type when single candidate

[Adam D. Ruppe via Digitalmars-d-learn]

On Monday, 29 March 2021 at 01:24:13 UTC, Preetpal wrote:
    writeln(isRandomAccessRange(arr));

Template arguments are passed by !(), not just ().

I believe you must also pass `typeof(arr)` since 
isRandomAccessRange is only interested in types.