On 03/16/2011 05:49 AM, Kagamin wrote:
Ali ǥhreli Wrote:
The following program may be surprising to the novice:
import std.stdio;
void main()
{
write("What is your name? ");
string name = readln();
writeln("Hi ", name, "!");
}
What if the user typed leading spaces? Will the program operate as you expect?
I would not like the leading spaces either, and that's another issue:
contrary to readln(), readf() leaves the newline character in the input.
I was about to start adopting the guideline of using " %s" (note the
space) when reading formatted unless there is a reason not to. Most of
the time the newline left from the previous input has nothing to do with
the next read.
Otherwise the following program gets stuck:
import std.stdio;
void main()
{
int i, j;
readf("%s%s", &i, &j);
}
As a result, my current guideline is "put a space before every format
specifier":
readf(" %s %s", &i, &j);
This is a departure from C's scanf but is more consistent.
I don't want to accept and teach buggy behavior and that's why I asked
on the D forum. Unfortunately I failed to attract interest there.
After accepting the above, I wanted to readf() lines too:
import std.stdio;
void main()
{
string s;
readf(" %s", &s);
writeln(s);
}
As another departure from C, readf() does not stop at the first
whitespace. It reads until the end of the input. Ok, I like that
behavior but it's not useful for "What is your name? " like inputs.
So it led me to readln().
I don't have a problem with whitespace being left in the line, I just
want to know whether that's the intended or accepted behavior.
Ali
