On Friday, 13 May 2022 at 11:58:15 UTC, zjh wrote:
On Friday, 13 May 2022 at 08:28:56 UTC, vit wrote:
...
```d
...
this(DataSources dataSources){
this.dataSources = dataSources;
}
...
return new MultiGraph!(staticMap!(PointerTarget, Ts))(ts);//ts
```
How is `ts` convert to `DataSources`?
`ts` have same type like `DataSources`:
```d
import std.meta : staticMap, allSatisfy;
import std.traits : PointerTarget, isPointer;
import std.conv : to;
alias Pointer(T) = T*;
class MultiGraph(Ts...){ // Ts == (float, double, int)
alias DataSources = staticMap!(Pointer, Ts); // (float,
double, int) -> (float*, double*, int*)
DataSources dataSources; // -> (float*, double*, int*)
float[][DataSources.length] buffers; // -> float[][3]
this(DataSources dataSources){ // dataSources == (float*,
double*, int*)
this.dataSources = dataSources;
}
void onTick() {
//grab datasource data and do something.
foreach(enum i, alias d; dataSources)
buffers[i] ~= to!float(*d); //or whatever
}
}
auto multiGraph(Ts...)(Ts ts) // Ts == (float*, double*, int*)
if(allSatisfy!(isPointer, Ts)){ //all types in Ts are pointers
alias DataSources = staticMap!(PointerTarget, Ts); //
(float*, double*, int*) -> (float, double, int)
return new MultiGraph!(DataSources)(ts);
}
void main(){
float myFloat;
double myDouble;
int myInteger;
auto g = multiGraph(&myFloat, &myDouble, &myInteger);
}
```
