On 6/5/22 14:04, Alain De Vos wrote:
> Could it be the copy constructor is only called during assignments (like
> C++).
The assignment operator is used during assignments both in C++ and D.
A confusion comes from the fact that construction uses the same operator
as assignment:
a = b; // Assignment because 'a' already exists
auto c = b; // Copy construction because 'c' is being constructed
> And for one, two there is an explicit assignment.
Actually, both are copy construction:
Foo one = Foo(1), two = 2;
You will never find me write code like because it's unclear. My version
would be the following:
Foo one = Foo(1);
Foo two = 2;
But even that is not my style because the first line repeats Foo and the
second line hides the fact that there is construction. So, this is what
I write in my programs:
auto one = Foo(1);
auto two = Foo(2);
> But not for three where there is a conversion ?
There are two "three"s in that code. The first one is construction (not
copy):
[one, two, Foo(3)]
And the other one is copy construction:
auto three = ++two;
'two' is first incremented and then a copy is made from 'two's new state.
Ali
