On 3/25/23 09:31, Olivier Prat wrote:
On Saturday, 25 March 2023 at 13:45:36 UTC, Olivier Prat wrote:
I'm trying to call assumeSorted on a const(Array) using this code
snippet:
[...]
In a similar fashion, a number of methods in SortedRange do not compile
if called on a const(SortedRange) or immutable(SortedRange), such as
length, or front. Is this on purpose?
There are a number of interesting points in your original post but I
couldn't find time to answer all of those.
I can inject this for now: :) assumeSorted returns a range object. The
concept of a const range object is flawed because by nature iteration of
a range happens by mutating it: For example, popBack has to do that.
So, it's normal that any range algorithm will assume a non-const object.
Ali
