On Tuesday, 4 June 2024 at 16:58:50 UTC, Basile B. wrote:
question in the header, code in the body, execute on a X86 or
X86_64 CPU
I understand that the notion of `bool` doesn't exist on X86,
hence what will be used is rather an instruction that write on
the lower 8 bits, but with a 7 bits corruption.
Do I corrupt memory here or not ?
Is that a safety violation ?
The problem is that while setIt() is @safe, your main function is
not. So the pointer cast (which is not @safe) is permitted.
A bool is a 1 byte type with two possible values : false (0) and
true (1).
When you set the value to false, you write 0 to the byte it
points to.
This is technically not a memory corruption, because as
bool.sizeof < int.sizeof, you just write the low order byte of an
int you allocated on the stack.
