Re: Wrap a call?

[monkyyy via Digitalmars-d-learn]

On Wednesday, 18 February 2026 at 19:43:38 UTC, JN wrote:

    import std;

    void before()
    {
        writeln("Before");
    }

    void after()
    {
        writeln("After");
    }

    void add(int x, int y)
    {
        writeln(x + y);
    }

    template WrapCall(string call)
    {
        enum WrapCall = "before(); " ~ call ~ "; after();";
    }

    void main()
    {
        mixin WrapCall!"add(1, 2)";
    }

This doesn't work, if I change it to mixin(WrapCall!"add(1, 2")), it works, why?

what do you mean why, thats a enum use this:

```d
void wrapcall(alias F,T...)(T args){
  before;
  F(args);
  after;
}
```