Hi Jesse, this won't work!
It's my fault in not explaining my problem well though...
I forget to mention something...
I'm using property syntax and try to call the method
Say I have
=====
private int _foo;
@property public int Foo() { return _foo; }
@property public void Foo(int value) { _foo = value; }
=====
if I call MEMBER(MyClass, "Foo")
I'd like to do some static test for "int Foo()" and "void Foo(int)"
So... how will I go on solving that?
"Jesse Phillips" wrote in message news:itdqs4$mv0$1...@digitalmars.com...
MemberDesc MEMBER(T, string memberName)() if(std.traits.hasMember!(T,
memberName))
{
...
}
Lloyd Dupont Wrote:
I have a MemberDesc class which describe a class's members.
I fill it with a template method like that (with GETTER and SETTER some
other templated method I wrote)
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MemberDesc MEMBER(T, string memberName)()
{
TypeInfo ti = typeid( typeof(__traits(getMember, T, memberName)) );
Variant function(Object target) getter = null;
getter = &GETTER!(T, memberName);
void function(Object target, Variant value) setter = null;
setter = &SETTER!(T, memberName);
return new MemberDesc(memberName, ti , getter, setter);
}
=====
And it works except that I don't do any check that the setter / getter
method exist!
I tried something like that
====
static if( __traits(compiles, __traits(getMember, T, member)) )
{
getter = &GETTER!(T, memberName);
}
====
but this always fail... mm.. how could I check for the getter?
and i guess it's even harder for the setter!
how about something like that (how to fix it?)
=====
static if( __traits(compiles, __traits(getMember, T, member) =
typeof(__traits(getMember, T, memberName)).init) )
{
setter = &SETTER!(T, memberName);
}
=====