Re: What is shared functions?

[simendsjo]

On 24.10.2011 17:23, Steven Schveighoffer wrote:
On Sun, 23 Oct 2011 08:32:34 -0400, simendsjo <simend...@gmail.com> wrote:
What does shared for functions mean? I thought it was supposed to
automatically synchronize access, but this doesn't seem to be the case.

void f() shared {
// no synchronization
}

void f() {
synchronized {
// do stuff
}
}

Shared functions do not affect the function. All they do is affect the
'this' pointer.

This:

struct S
{
void f() shared {}
}

is roughly equivalent to this:

struct S
{}

void f(shared ref Foo this){}

-Steve


So you cannot create a function to be called on both shared and unshared 
instances? For mutable/immutable there's const, but there is no 
"maybeShared".

struct S {
    void onlyShared() shared {}
    void notShared() {}
}

void main() {
    shared s1 = cast(shared)new S();
    s1.onlyShared(); // ok
    //s1.notShared(); // error: not callable using argument types () shared
    auto s2 = new S();
    //s2.onlyShared(); // error: not callable using argument types ()
    s2.notShared(); // ok
}