On Thu, 08 Mar 2012 14:49:12 -0500, H. S. Teoh <[email protected]>
wrote:
On Thu, Mar 08, 2012 at 08:22:05PM +0100, Timon Gehr wrote:
On 03/08/2012 08:09 PM, H. S. Teoh wrote:
[...]
>The problem is, how to write this function so that it can be called
from
>*both* a const public method and a non-const public method? Since the
>method itself doesn't actually modify anything, it *should* in theory
be
>possible to mark it as const:
>
> const Slot *findSlot(Key key) { ... }
>
>However, because the const applies to 'this', the compiler insists that
>referencing anything via 'this', including reading a pointer to a slot,
>must also be const, so it refuses to let the return type be Slot*; it
>has to be const(Slot)*.
>
>But this is silly, because now the caller isn't allowed to modify the
>Slot either, so now I need to bloat the code with two identical copies
>of findSlot, one with const, and one without (since if it wasn't marked
>const, then a const method couldn't call it).
[...]
inout(Slot)* findSlot(Key key) inout { ... }
Ahhh. Thanks!
But that still doesn't solve the problem:
inout(Slot)* findSlot(Key key) inout {
auto slot = slots[hash(key)];
What is type slot, and how is it constructed? This snippit isn't enough
to provide help.
while (slot) {
if (slot.hash == hash(key) && slot.key == key)
return slot;
// Error: cannot modify inout(Slot)*
An exact message is preferrable.
---> slot = slot.next;
}
return null;
}
-Steve
