Re: Higher-order functions?

[Jacob Carlborg]

On 2012-04-11 10:45, Xan wrote:

Good answer.

For the other hand, what is the simplest method for implementing this
(in pseucode) in D:

Sure:

FUNC someprocedure(int a, int b, func<int, int: int> f) int
RETURN f(a, b)
}

And call it with:

IO.writeLine("add: " .. someprocedure(2, 3, { a, b => a + b }))
IO.writeLine("multiply: " .. someprocedure(2, 3, { a, b => a * b }))

(Read the => as "gives")

Is it possible to have this?

If I understand the above code correctly:

import std.stdio;

int someprocedure (int a, int b, int delegate (int, int) f)
{
    return f(a, b);
}

void main ()
{
    writeln("add: ", someprocedure(2, 3, (a, b) => a + b));
    writeln("multiply: ", someprocedure(2, 3, (a, b) => a * b));
}

--
/Jacob Carlborg