Re: Memoizing a templated function

[bearophile]

ixid:

Memoizing a templated version of a function doesn't seem to 
work,

A template isn't a function, it's just a recipe to define a 
function given one or more compile-time values or types. So 
memoize works if you instantiate in some way the template:

import std.functional;

int test(int n) {
    return n * n;
}

T test2(T)(T n) {
    return n * n;
}

void main() {
    int n = 5;
    n = memoize!test(n); // OK
    n = test2(n); // OK
    n = memoize!(test2!int)(n); // OK
    n = memoize!(test2!(typeof(n)))(n); // OK
}


Bye,
bearophile