Re: Why must bitfields sum to a multiple of a byte?

[Era Scarecrow]

On Tuesday, 31 July 2012 at 00:00:24 UTC, Era Scarecrow wrote:
Corrections:
 So, 2 variables using 4 bit ints would be

void a(int v) @property {
  value &= ~(0x7 << 4);
  value |= (v & 0x7) << 4;
}

the second setter should be
 void b(int v) @property {