On 08/22/2012 11:51 AM, Ellery Newcomer wrote:
> hey.
>
> is this valid code?
>
> void func1(int i, double j = 1.0) {
> }
>
> void main() {
> auto fn = &func1;
> func1(1); //dmd: ok
> fn(1); // dmd: not ok
> }The type of the function pointer does not include the values of the default parameters.
The type of fn is "a function taking int and a double, returning nothing". So the compiler must require that information at the call site.
The alternative could work too: The compiler could keep a table from function pointers to default parameters. But that would be slow.
I am not surprised by dmd's behavior. Ali
