how to get fully qualified name of a template function?
In the code below I want to get "util.mod.mymethod!(double)"
I tried everything (see below) to no avail, it just returns
"mymethod";
The closest I get is demangle(mangledName!(fun)), which shouldn't
be hard to convert to what I want, but demangle is runtime, not
compile time.
Ideally, fullyQualifiedName should do that, but currently fails.
(btw I have a fix for another bug with fullyQualifiedName with
non-templated functions which I can post shortly).
----
module util.mod;
import std.stdio;
import std.traits;
import core.demangle;
void mymethod(T)(){}
void main(){ fun_aux!(mymethod!double);}
void fun_aux(alias fun)(){
pragma(msg,fun);
writeln(fun.stringof);
writeln(__traits(identifier,fun));
writeln(__traits(identifier,__traits(parent,fun)));
pragma(msg, mangledName!(fun));
writeln(demangle(mangledName!(fun)));
//pragma(msg, demangle(mangledName!(fun)));//CT error:demangle
is runtime
//writeln(fullyQualifiedName!fun);//CT error
----
