On Fri, 14 Sep 2012 13:03:37 -0400, bearophile <bearophileh...@lycos.com>
wrote:
monarch_dodra:
int *p = [5].ptr;
-Steve
But see this benchmark:
void main() {
auto pointers = new int*[1_000_000];
foreach (int i, ref p; pointers)
p = [i].ptr;
foreach (i; 0U .. 4_000_000_000U) {}
}
On my 32 bit system its RAM commit is about 23 MB. The pointers array
takes about 4 MB. This means each "int" takes about 19 bytes of heap RAM
instead of 4. Each int allocates some data (capacity) to extend the
array.
That has nothing to do with using array literals -- it has to do with the
fact that the minimum heap block is 16-bytes (or 4 ints wide). Extra 3
bytes is probably for overhead and static data.
If instead of p = [i].ptr; you did p = new int; *p = i;
You would get the same exact behavior.
No way around this, unless you want to do custom allocators.
-Steve
