On Monday, 24 September 2012 at 15:05:54 UTC, Jason Spencer wrote:
I imagine there's a slick way to do this, but I'm not seeing it.

I have a string of hex digits which I'd like to convert to an array of 8 ubytes:

0123456789abcdef --> [0x01, 0x23, 0x45, 0x67, 0x89, 0xAB, 0xCD, 0xEF]

I'm looking at std.format.formattedRead, but the documentation is...lightish. First of all, it seems there's no format specifier except %s on reads and type information is gleaned from the args' types. I was able to experiment and show that %x works, but no documentation on exactly how.

Second, array syntax seems to work only if there's some delimiter. With:

void main(string[] args)
{
   ubyte[8] b;

   formattedRead(args[1], "%(%s%)", &b);
}

I get

std.conv.ConvOverflowException@C:\Tools\D\dmd2\windows\bin\..\..\src\phobos\std\
conv.d(2006): Overflow in integral conversion

at least once. :) But that makes sense--hard to tell how many input chars to assign to one byte versus another (although it seems to me a hungry algorithm would work--saturate one type's max and move to the next.)

There doesn't seem to be any support for field sizes or counts in formatted read, similar to old C "%16x". This barks at me right away--"%1 not supported."

I know I could read (in this case) as two longs or a uint16, but I don't want to deal with endianess--just data.

Is there some trick to use the fact that b is fixed size 8 bytes and know that requires 16 hex digits and converts automatically? Is there some other suggestion for how to do this eloquently? I can play around with split and join, but it seemed like there is probably some way to do this directly that I'm not seeing.

Thanks!
Jason

I think that you are not supposed to use a static array: If there are not EXACTLY as many array elements as there are parse-able elements, then the formatted read will consider the parse to have failed.

Try this, it's what you want, right?

--------
void main()
{
    string s = "ffff fff ff f";
    ushort[] vals;
    formattedRead(s, "%(%x %)", &vals);
    writefln("%(%s - %)", vals);
}
--------
65535 - 4095 - 255 - 15
--------

Regarding the %1x, well, I guess it just isn't supported (yet?)

Reply via email to