Struct members align in DMD 2.060

[novice2]

Some of my code broken in DMD 2.060.
I need packed struct without align to process data.
Is this bug or something changed in 2.060 ?
Code http://dpaste.dzfl.pl/212ca53b :

import std.stdio;

align(1) struct S1
{
  char[2]  c;  //+0
  uint     u;  //+2
}

struct S2
{
  align(1):
  char[2]  c;  //+0
  uint     u;  //+2
}

struct S3
{
  align(1) char[2]  c;  //+0
  align(1) uint     u;  //+2
}

void main()
{
  writeln("**** compiler ",__VENDOR__, " ", __VERSION__);
  writeln;

  writeln("S1.c.offsetof (should be 0) = ", S1.c.offsetof);
  writeln("S1.u.offsetof (should be 2) = ", S1.u.offsetof);
  writeln("S1.sizeof (should be 6) = ", S1.sizeof);
  writeln;

  writeln("S2.c.offsetof (should be 0) = ", S2.c.offsetof);
  writeln("S2.u.offsetof (should be 2) = ", S2.u.offsetof);
  writeln("S2.sizeof (should be 6) = ", S2.sizeof);
  writeln;

  writeln("S3.c.offsetof (should be 0) = ", S3.c.offsetof);
  writeln("S3.u.offsetof (should be 2) = ", S3.u.offsetof);
  writeln("S3.sizeof (should be 6) = ", S3.sizeof);
  writeln;
}


Output:

**** compiler Digital Mars D 2059

S1.c.offsetof (should be 0) = 0
S1.u.offsetof (should be 2) = 2
S1.sizeof (should be 6) = 6

S2.c.offsetof (should be 0) = 0
S2.u.offsetof (should be 2) = 2
S2.sizeof (should be 6) = 6

S3.c.offsetof (should be 0) = 0
S3.u.offsetof (should be 2) = 2
S3.sizeof (should be 6) = 6


**** compiler Digital Mars D 2060

S1.c.offsetof (should be 0) = 0
S1.u.offsetof (should be 2) = 4
S1.sizeof (should be 6) = 8

S2.c.offsetof (should be 0) = 0
S2.u.offsetof (should be 2) = 2
S2.sizeof (should be 6) = 8

S3.c.offsetof (should be 0) = 0
S3.u.offsetof (should be 2) = 2
S3.sizeof (should be 6) = 8