deed:
// Again, why are the three last adresses the same?
The D language and its compiler is acting correctly here, so the output you see is correct. All those structs are allocated on the stack. The first three Test are allocated on the stack. In the loop it allocates the first struct on the stack, and it gets destroyed. Then when the successive loop enters, it creates a new struct, and it uses the same stack space.
See: import std.stdio; struct Test { static Test*[] psObject; int x; this(int a) { x = a; psObject ~= &this; } ~this() { writeln(x); } } void main() { Test(0); foreach (i; 1 .. 3) Test(i); Test.psObject.writeln(); } 0 1 2 [12FE48, 12FE54, 12FE54] Bye, bearophile