On 2012-23-15 16:10, Simen Kjaeraas <simen.kja...@gmail.com> wrote:
On 2012-05-15 16:10, Namespace <rswhi...@googlemail.com> wrote:
How can I do this?
I have this code: http://dpaste.dzfl.pl/d9165502
And as you can see, the templated function 'receive2' take
automatically dynamic arrays. But how can I tell the compiler, that
this function takes (preferably) static arrays?
My little "hack" function 'receive' take the type and the number of
elements. So the compiler know: it's a static array. But is there no
simpler trick to do this?
Maybe something like 'void receive(T)(static T vals) {'.
Nope. That's the way to do it.
No, wait, sorry. You don't need to specify those things when calling the
function. This works:
void bar(T, size_t n)(T[n] a) {}
void main(){
int[3] a;
bar(a);
}
--
Simen
