On Tuesday, 6 November 2012 at 18:34:04 UTC, Ali Çehreli wrote:
Because in the case of cs, T is 'const(S)', matching the
following two instantiations:
1) ref const(S) i
2) const ref const(S) i
The second line has a redundant const. So, they end up having
the same signature.
Ali
Oh - that clears it up, thanks. G(T)(ref T i) is really
potentially many functions whereas g(ref S i) is only one and no
conflict. What is the standard approach in the face of templates
to differentiate between const(T) and T?
If templates do you always do something like:
void G(T)(ref T i) if(isMutable!T) { }
void G(T)(const ref T i) { }
Thanks,
Dan
