On Thursday, 10 January 2013 at 23:49:40 UTC, monarch_dodra wrote:
On Thursday, 10 January 2013 at 23:37:14 UTC, Namespace wrote:
Without a declared opAssign, this
S s3;
s3 = s1;
also calls the postblit. That is strange.
If there is no user declared opAssign, then opAssign is
implemented in terms of postblit. It's designed that way.
This is kind of like C++'s copy and swap idiom, but built into
the language.
And that was what I did not know and could not find anywhere. So
it is enough if I declare a postblit.
And yes, benchmarks are hard. ;)
