On 04/17/2013 04:48 PM, rbt...@digitalpath.net wrote:
I said:
> That doesn't look right: char is a UTF-8 code unit. Unless you are sure
> that the file contains UTF-8, I recommend you use something else, e.g.
> ubyte.
You said:
> It' a pure ascii file.
That means that every byte value in the file is in the range [0, 127],
right? ASCII...
> string c = to!string (buf[107..111]);
For that to work, every one of those bytes must be in the range [0, 127].
> if (c == " ") break;
> int z = to!int(c);
The fact that you are trying to convert those four bytes to a 32 value
makes me think that the file is not "pure ascii" after all. Unless the
int value written in that location of the file has the property that
none of the four 8 bits of it are above 127.
However, I don't understand whether your actual problem is related to that.
Ali
