On Friday, 28 June 2013 at 16:04:35 UTC, Benjamin Thaut wrote:
I'm currently making a few tests with std.algorithm, std.range,
etc
I have a arry of words. Is it possible to count how often each
word is contained in the array and then sort the array by the
count of the individual words by chaining ranges? (e.g. without
using a foreach loop + hashmap)?
If you don't mind sorting twice:
words.sort()
.group()
.array()
.sort!((a, b)=> a[1] > b[1])
.map!(a => a[0])
.copy(words);
You could also do it with a hashmap to keep the count.
